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Discuss the continuity of the cosine, cosecant, secant and cotangent functions, - Mathematics

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प्रश्न

Discuss the continuity of the cosine, cosecant, secant and cotangent functions,

योग

उत्तर

(i) f (x) = cos (x)

Let c be any real number.

If f(x) is continuous at x = c, this implies:

f(c) = `lim_(x -> c^+)  f(x) = lim_(x -> c^-)  f (x)`

⇒ (cos c) = (cos c) = (cos c)

which is true, i.e. f(x) is continuous at every point on the real number line.

(ii) f(x) = cosec (x)

Let c be any real number.

If f(x) is continuous at x = c, this implies:

f(c) = `lim_(x ->^+) f(x) = lim_(x -> c^-) f(x)`

`=>` (cosec c) = (cosec c) = (cosec c)

which is true, i.e. f(x) is continuous at every point on the real number line.

(iii) f(x) = sec (x)

Let c be any real number.

If f(x) is continuous at x = c, this implies:

f(c) = `lim_(x -> c^+)  f(x) = lim_(x -> c^-)  f(x)`

`=>` (sec c) = (sec c) = (sec c)

which is true, i.e. f(x) is continuous at every point on the real number line.

(iv) f(x) = cot (x)

Let c be any real number such that (n - 1)`pi < x < npi,` where n represents an integer point.

If f(x) is continuous at x = c, this implies:

f(c) `= lim_(x -> c^+)  f (x) = lim_(x -> c^-)  f(x)`

`=>` (cot c) = (cot c) = (cot c)

Which is true, i.e. f(x) is continuous at every point on the real number line between (n - 1)`pi` and `n pi`.

Now if we consider c such that c = `n pi` where n represents an integer point, then:

If f(x) is continuous at x = c, this implies:

f(c) `= lim_(x -> c^+)  f(x) = lim_(x -> c^-)  f(x)`

`=> pm infty = pm infty = pm infty`

That is, f(x) is continuous at every point on the real number line except at the `n pi` type points.

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अध्याय 5: Continuity and Differentiability - Exercise 5.1 [पृष्ठ १६०]

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एनसीईआरटी Mathematics [English] Class 12
अध्याय 5 Continuity and Differentiability
Exercise 5.1 | Q 22 | पृष्ठ १६०

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