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Evaluate the following: 5 sec 68 ° cosec 22 ° + 3 sin 52 ° sec 38 ° cot 51 ° cot 39 ° - Mathematics

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प्रश्न

Evaluate the following: `(5sec68°)/("cosec"22°) + (3sin52° sec38°)/(cot51° cot39°)`

योग

उत्तर

`(5sec68°)/("cosec"22°) + (3sin52° sec38°)/(cot51° cot39°)`

= `(5sec(90° - 22°))/("cosec"22°) + (3sin52° sec(90° - 52°))/(cot51° cot(90° - 51°)`

= `(5cos22°)/("cosec"22°) + (3sin52° "cosec"52°)/(cot51° tan51°)`

= `5 + (3sin52° xx 1/(sin52°))/(cot51° xx 1/(cot51°)`

= `5 + (3)/(1)`
= 5 + 3
= 8.

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Trigonometric Equation Problem and Solution
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 27: Trigonometrical Ratios of Standard Angles - Exercise 27.3

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फ्रैंक Mathematics [English] Class 9 ICSE
अध्याय 27 Trigonometrical Ratios of Standard Angles
Exercise 27.3 | Q 3.4
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