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Evaluate the following: 2 sin 28 ° cos 62 ° + 3 cot 49 ° tan 41 ° - Mathematics

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प्रश्न

Evaluate the following: `(2sin28°)/(cos62°) + (3cot49°)/(tan41°)`

योग

उत्तर

`(2sin28°)/(cos62°) + (3cot49°)/(tan41°)`

= `(2sin(90° - 62°))/(cos62°) + (3cot(90° - 41°))/(tan41°)`

= `(2cos62°)/(cos62°) + (3tan41°)/(tan41°)`

= 2 + 3
= 5.

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Trigonometric Equation Problem and Solution
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 27: Trigonometrical Ratios of Standard Angles - Exercise 27.3

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फ्रैंक Mathematics [English] Class 9 ICSE
अध्याय 27 Trigonometrical Ratios of Standard Angles
Exercise 27.3 | Q 3.3
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