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Examine the continuity of the following: ex tan x - Mathematics

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प्रश्न

Examine the continuity of the following:

ex tan x

योग

उत्तर

Let f(x) = ex tan x

f(x) is defined at ail points of R.

Expect at `(2"n" + 1) pi/2`, n ∈ Z.

Let x0 be an arbitrary point in `"R" - (2"n" + 1) pi/2`, n ∈ Z

Then `lim_(x -> x_0) f(x) =  lim_(x -> x_0) "e"^x tan x`

= `"e"^(x_0)  tan x_0`  .......(1)

`f(x_0) = "e"^(x_0)  tan x_0`  .......(2)

From equation (1) and (2) we get

`lim_(x -> x_0)  "e"^x  tan x = f(x_0)`

∴ Limit at x = x0 exist and is equal to the value of the function f(x) at x = x0.

Since x0 is arbitrary the limit of the function. f(x) exists at all points in `"R" - (2"n" + 1) pi/2`, n ∈ Z and is equal to the value of the function f(x) at that points.

∴ f(x) satisfies all conditions for continuity.

Hence, f(x) is continuous at all points of `"R" - (2"n" + 1) pi/2`, n ∈ Z

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Continuity
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 9: Differential Calculus - Limits and Continuity - Exercise 9.5 [पृष्ठ १२७]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 9 Differential Calculus - Limits and Continuity
Exercise 9.5 | Q 2. (iii) | पृष्ठ १२७

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