Advertisements
Advertisements
प्रश्न
Expand.
(101)3
योग
उत्तर
(101)3
= `(100 + 1)^3`
= `(100)^3 + (1)^3 + 3 xx (100)^2 xx 1 + 3 xx 100 xx (1)^2`
= 1000000 + 1 + 30000 + 300
= 1030301
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
संबंधित प्रश्न
Expand.
(7x + 8y)3
Expand.
`((5x)/y + y/(5x))^3`
Find the cube of : `( 3a - 1/a ) (a ≠ 0 )`
If `a^2 + 1/a^2` = 18; a ≠ 0 find :
(i) `a - 1/a`
(ii) `a^3 - 1/a^3`
Use property to evaluate : 133 + (-8)3 + (-5)3
Expand : (3x + 5y + 2z) (3x - 5y + 2z)
If X ≠ 0 and X + `1/"X"` = 2 ; then show that :
`x^2 + 1/x^2 = x^3 + 1/x^3 = x^4 + 1/x^4`
If `"a" - (1)/"a" = 7`, find `"a"^2 + (1)/"a"^2 , "a"^2 - (1)/"a"^2` and `"a"^3 - (1)/"a"^3`
If p - q = -1 and pq = -12, find p3 - q3
(p + q)(p2 – pq + q2) is equal to _____________
