हिंदी

Express the Following in Terms of Log 2 and Log 3: Log 225 16 − 2 Log 5 9 + Log ( 2 3 ) 5 - Mathematics

Advertisements
Advertisements

प्रश्न

Express the following in terms of log 2 and log 3: `"log"(225)/(16) - 2"log"(5)/(9) + "log"(2/3)^5`

योग

उत्तर

`"log"(225)/(16) - 2"log"(5)/(9) + "log"(2/3)^5`

= `"log"(225)/(16) - 2"log"(5)/(9) + 5"log"(2)/(3)`

= log225 - log16 - 2[log5 - log9] + 5[log2 - log3]
= log(52 x 32) - log24 - 2[log5 - log32] + 5[log2 - log3]
= log52 + log32 - 4log2 - 2[log 5 - 2log3] + 5[log2 - log3]
= 2log5 + 2log3 - 4log2 - 2log5 + 4log3 + 5log2 - 5log3
= log2 + log3.

shaalaa.com
Expansion of Expressions with the Help of Laws of Logarithm
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 10: Logarithms - Exercise 10.2

APPEARS IN

फ्रैंक Mathematics [English] Class 9 ICSE
अध्याय 10 Logarithms
Exercise 10.2 | Q 3.5
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×