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प्रश्न
Find the cube of: `3"a" + (1)/(3"a")`
योग
उत्तर
`(3"a" + 1/(3"a"))^3`
= `(3"a")^3 + (1/(3"a"))^3 + 3 (3"a") (1/(3"a")) (3"a" + 1/(3"a"))`
= `27"a"^3 + (1)/(27"a"^3) + 9"a" + (1)/"a"`.
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