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प्रश्न
Find the cube of: `4"p" - (1)/"p"`
योग
उत्तर
`(4"p" - (1)/"p")^3`
= `(4"p")^3 - (1/"p")^3 - 3(4"p") (1/"p") (4"p" - 1/"p")`
= `64"p"^3 - (1)/"P"^3 - 48"p" + (12)/"p"`.
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