Advertisements
Advertisements
प्रश्न
The sum of two numbers is 9 and their product is 20. Find the sum of their (i) Squares (ii) Cubes
उत्तर
Given sum of two numbers is 9 and their product is 20.
Let the numbers be a and b.
a + b = 9
ab = 20
Squaring on both sides gives
(a+b)2 = 92
a2 + b2 + 2ab = 81
a2 + b2 + 40 = 81
So sum of squares is 81 - 40 = 41
Cubing on both sides gives
(a + b)3 = 93
a3 + b3 + 3ab(a + b) = 729
a3 + b3 + 60(9) = 729
a3 + b3 = 729 - 540 = 189
So the sum of cubes is 189.
APPEARS IN
संबंधित प्रश्न
Expand.
(52)3
Expand.
`(x + 1/x)^3`
Use property to evaluate : 383 + (-26)3 + (-12)3
If a ≠ 0 and `a- 1/a` = 3 ; Find :
`a^3 - 1/a^3`
Find the cube of: `3"a" + (1)/(3"a")`
If `x + (1)/x = 5`, find the value of `x^2 + (1)/x^2, x^3 + (1)/x^3` and `x^4 + (1)/x^4`.
If `"p" + (1)/"p" = 6`; find : `"p"^3 + (1)/"p"^3`
If a + b + c = 0; then show that a3 + b3 + c3 = 3abc.
If x + 2y = 5, then show that x3 + 8y3 + 30xy = 125.
Evaluate the following :
(5.45)3 + (3.55)3