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प्रश्न
Find the median of the following distribution:
| Marks | 0 – 10 | 10 –20 | 20 – 30 | 30 – 40 | 40 – 50 | 50 – 60 |
| Number of students | 5 | 8 | 20 | 15 | 7 | 5 |
उत्तर
| Marks | No. of students (f) |
c.f. |
| 0 – 10 | 5 | 5 |
| 10 – 20 | 8 | 13 |
| 20 – 30 | 20 | 33 |
| 30 – 40 | 15 | 48 |
| 40 – 50 | 7 | 55 |
| 50 – 60 | 5 | 60 |
| `sum"f"` = 60 |
Here, N = `sum"f"` = 60
∴ `"N"/2 = 60/2` = 30
So, the median class is 20 – 30
Lower limit of median class, l = 20
Class size, h = 10
Cumulative frequency of preceding class, c.f. = 13
Frequency of median class, f = 20
∴ Median = `"l" + (("N" / 2 - "c.f."))/"f" xx "h"`
= `20 + ((60 /2 - 13)/20) xx 10`
= `20 + 17/2`
= 20 + 8.5
= 28.5
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