Advertisements
Advertisements
प्रश्न
Find the value of 'A', if 2 sin 2A = 1
उत्तर
2 sin 2A = 1
⇒ sin 2A = `(1)/(2)`
⇒ sin 2A = sin30°
⇒ 2A = 30°
⇒ A = 15°.
APPEARS IN
संबंधित प्रश्न
Calculate the value of A, if (sin A - 1) (2 cos A - 1) = 0
If 4 cos2 x° - 1 = 0 and 0 ∠ x° ∠ 90°,
find:(i) x°
(ii) sin2 x° + cos2 x°
(iii) `(1)/(cos^2xx°) – (tan^2 xx°)`
If θ = 15°, find the value of: cos3θ - sin6θ + 3sin(5θ + 15°) - 2 tan23θ
In the given figure, PQ = 6 cm, RQ = x cm and RP = 10 cm, find
a. cosθ
b. sin2θ- cos2θ
c. Use tanθ to find the value of RQ
Find the value of 'x' in each of the following:
Find the value 'x', if:
Find x and y, in each of the following figure:
Evaluate the following: `(sin0° sin35° sin55° sin75°)/(cos22° cos64° cos58° cos90°)`
Evaluate the following: `(3sin^2 40°)/(4cos^2 50°) - ("cosec"^2 28°)/(4sec^2 62°) + (cos10° cos25° cos45° "cosec"80°)/(2sin15° sin25° sin45° sin65° sec75°)`
Prove the following: tanθ tan(90° - θ) = cotθ cot(90° - θ)
