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प्रश्न
For the differential equation, find the general solution:
(ex + e–x) dy – (ex – e–x) dx = 0
उत्तर
(ex + e-x) dy = (ex - e-x) dx = 0
⇒ `dy = ((e^x - e^(-x))/(e^x + e^(-x))) dx`
On integrating
`int 1. dy = int ((e^x - e^(-x))/(e^x + e^(-x))) dx`
y = log (ex + e-x) + C
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