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प्रश्न
For the differential equation, find the general solution:
`dy/dx = (1+x^2)(1+y^2)`
उत्तर
We have, `dy/dx = (1 + x^2) (1 + y^2)`
⇒ `dy/(1 + y^2) = (1 + x^2) dx` ...(i)
Integrating (i) both sides, we get
⇒ `tan^-1 y = x + 1/3 x^3 + C`
Which is the required solution.
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