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From the Point of a Tower 100m High, a Man Observe Two Cars on the Opposite Sides to the Tower with Angles of Depression 30° and 45 Respectively. Find the Distance Between the Cars - Mathematics

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प्रश्न

From the point of a tower 100m high, a man observe two cars on the opposite sides to the tower with angles of depression 30° and 45 respectively. Find the distance between the cars

उत्तर

Let PQ be the tower
We have,
PQ = 100m, ∠PQR = 30° and ∠PBQ = 45°
In ΔAPQ,

`tan 30° = (PQ)/(AP)`

`⇒ 1/ sqrt(3) = 100/(AP)`

`⇒AP = 100 sqrt(3) m`

Also, in ΔBPQ,

` tan 45° = (PQ)/(BP)`

`⇒ 1 = 100/(BP)`

⇒ BP = 100M

Now , AB = AP+ BP 

   `= 100 sqrt(3) + 100`

   `= 100( sqrt(3) +1)`

   `= 100 xx (1.73 +1 )`

   ` = 100 xx 2.73` 

    = 273 m 

So, the distance between the cars is 273m.

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अध्याय 14: Height and Distance - Exercises

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आरएस अग्रवाल Mathematics [English] Class 10
अध्याय 14 Height and Distance
Exercises | Q 13

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