हिंदी
तमिलनाडु बोर्ड ऑफ सेकेंडरी एज्युकेशनएचएससी विज्ञान कक्षा १२

Identify the type of conic and find centre, foci, vertices, and directrices of the following: (x+1)/100+(y-2)264 = 1 - Mathematics

Advertisements
Advertisements

प्रश्न

Identify the type of conic and find centre, foci, vertices, and directrices of the following:

`(x + 1)^2/100 + (y - 2)^2/64` = 1

योग

उत्तर

It is an ellipse.

The major axis is parallel to the x-axis.

a2 = 100, b2 = 64

a = 10, b = 8

c2 = a2 – b2

= 100 – 64 = 36

c = 6

ae = 6

10e = 6

e = `6/10 = 3/5`

Centre (h, k) = (– 1, 2)

Vertices (h ± a, k) = (– 1 ± 10, 2)

= (– 1 + 10, 2) and (– 1 – 10, 2)

= (9, 2) and (– 11, 2)

Foci (h ± c, k) = (– 1 ± 6, 2)

= (– 1 + 6, 2) and (– 1 – 6, 2)

= (5, 2) and (– 7, 2)

Directrix x = `+-  "a"/"e" + "h"`

= `+-  10/(3/5) - 1`

= `+-  50/3 - 1`

x = `50/3 - 1` and x = `50/(-3) - 1`

= `47/3`  and `(- 53)/5`

shaalaa.com
Conics
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Two Dimensional Analytical Geometry-II - Exercise 5.2 [पृष्ठ १९७]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 12 TN Board
अध्याय 5 Two Dimensional Analytical Geometry-II
Exercise 5.2 | Q 8. (ii) | पृष्ठ १९७

संबंधित प्रश्न

Find the equation of the parabola whose focus is the point F(-1, -2) and the directrix is the line 4x – 3y + 2 = 0.


The parabola y2 = kx passes through the point (4, -2). Find its latus rectum and focus.


Find the co-ordinates of the focus, vertex, equation of the directrix, axis and the length of latus rectum of the parabola

x2 = 8y


The eccentricity of the parabola is:


The double ordinate passing through the focus is:


The equation of directrix of the parabola y2 = -x is:


Find the equation of the parabola in the cases given below:

Passes through (2, – 3) and symmetric about y-axis


Find the equation of the parabola in the cases given below:

Vertex (1, – 2) and Focus (4, – 2)


Find the equation of the hyperbola in the cases given below:

Centre (2, 1), one of the foci (8, 1) and corresponding directrix x = 4


Find the equation of the hyperbola in the cases given below:

Passing through (5, – 2) and length of the transverse axis along x-axis and of length 8 units


Find the vertex, focus, equation of directrix and length of the latus rectum of the following:

x2 = 24y


Identify the type of conic and find centre, foci, vertices, and directrices of the following:

`x^2/25 - y^2/144` = 1


Identify the type of conic and find centre, foci, vertices, and directrices of the following:

`y^2/16 - x^2/9` = 1


Prove that the length of the latus rectum of the hyperbola `x^2/"a"^2 - y^2/"b"^2` = 1 is `(2"b"^2)/"a"`


Show that the absolute value of difference of the focal distances of any point P on the hyperbola is the length of its transverse axis


Identify the type of conic and find centre, foci, vertices, and directrices of the following:

18x2 + 12y2 – 144x + 48y + 120 = 0


Choose the correct alternative:

The eccentricity of the hyperbola whose latus rectum is 8 and conjugate axis is equal to half the distance between the foci is


Choose the correct alternative:

If P(x, y) be any point on 16x2 + 25y2 = 400 with foci F(3, 0) then PF1 + PF2 is


Choose the correct alternative:

If x + y = k is a normal to the parabola y2 = 12x, then the value of k is 14


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×