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प्रश्न
If 4 sinθ = 3 cosθ, find tan2θ + cot2θ
उत्तर
4 sinθ = 3 cosθ
⇒ `(sin θ)/(cos θ) = (3)/(4)`
⇒ tan θ = `(sin θ)/(cos θ) = (3)/(4)`
⇒ cot θ = `(1)/(tanθ) = (4)/(3)`
tan2θ + cot2θ =
= `(3/4)^2 + (4/3)^2`
= `(9)/(16) + (16)/(9)`
= `(81 + 256)/(144)`
= `(337)/(144)`.
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