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Chapters
2: Profit , Loss and Discount
3: Compound Interest
4: Expansions
5: Factorisation
6: Changing the subject of a formula
7: Linear Equations
8: Simultaneous Linear Equations
9: Indices
10: Logarithms
11: Triangles and their congruency
12: Isosceles Triangle
13: Inequalities in Triangles
14: Constructions of Triangles
15: Mid-point and Intercept Theorems
16: Similarity
17: Pythagoras Theorem
18: Rectilinear Figures
19: Quadrilaterals
20: Constructions of Quadrilaterals
21: Areas Theorems on Parallelograms
22: Statistics
23: Graphical Representation of Statistical Data
24: Perimeter and Area
25: Surface Areas and Volume of Solids
▶ 26: Trigonometrical Ratios
27: Trigonometrical Ratios of Standard Angles
28: Coordinate Geometry
![Frank solutions for Mathematics [English] Class 9 ICSE chapter 26 - Trigonometrical Ratios Frank solutions for Mathematics [English] Class 9 ICSE chapter 26 - Trigonometrical Ratios - Shaalaa.com](/images/mathematics-english-class-9-icse_6:c41cc344f5174c64a036c55d113af73f.jpg)
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Solutions for Chapter 26: Trigonometrical Ratios
Below listed, you can find solutions for Chapter 26 of CISCE Frank for Mathematics [English] Class 9 ICSE.
Frank solutions for Mathematics [English] Class 9 ICSE 26 Trigonometrical Ratios Exercise 26.1
In each of the following, one trigonometric ratio is given. Find the values of the other trigonometric.
sinA = `(12)/(13)`
In each of the following, one trigonometric ratio is given. Find the values of the other trigonometric.
cosB = `(4)/(5)`
In each of the following, one trigonometric ratio is given. Find the values of the other trigonometric.
cotA = `(1)/(11)`
In each of the following, one trigonometric ratio is given. Find the values of the other trigonometric.
cose C = `(15)/(11)`
In each of the following, one trigonometric ratio is given. Find the values of the other trigonometric.
tan C = `(5)/(12)`
In each of the following, one trigonometric ratio is given. Find the values of the other trigonometric.
sinB = `sqrt(3)/(2)`
In each of the following, one trigonometric ratio is given. Find the values of the other trigonometric.
cos A = `(7)/(25)`
In each of the following, one trigonometric ratio is given. Find the values of the other trigonometric.
tanB = `(8)/(15)`
In each of the following, one trigonometric ratio is given. Find the values of the other trigonometric.
sec B = `(15)/(12)`
In each of the following, one trigonometric ratio is given. Find the values of the other trigonometric.
cosec C = `sqrt(10)`
In ΔABC, ∠A = 90°. If AB = 5 units and AC = 12 units, find: sinB
In ΔABC, ∠A = 90°. If AB = 5 units and AC = 12 units, find: cos C
In ΔABC, ∠A = 90°. If AB = 5 units and AC = 12 units, find: tan B.
In ΔABC, ∠B = 90°. If AB = 12units and BC = 5units, find: sinA
In ΔABC, ∠B = 90°. If AB = 12units and BC = 5units, find: tan A
In ΔABC, ∠B = 90°. If AB = 12units and BC = 5units, find: cos C
In ΔABC, ∠B = 90°. If AB = 12units and BC = 5units, find: cot C
If sinA = `(3)/(5)`, find cosA and tanA.
If cosB = `(1)/(3)` and ∠C = 90°, find sin A, and B and cot A.
If sin θ = `(8)/(17)`, find the other five trigonometric ratios.
If tan = 0.75, find the other trigonometric ratios for A.
If sinA = 0.8, find the other trigonometric ratios for A.
If 8 tanθ = 15, find (i) sinθ, (ii) cotθ, (iii) sin2θ - cot2θ
In the given figure, PQR is a triangle, in which QS ⊥ PR, QS = 3 cm, PS = 4 cm and QR = 12 cm, find the value of: sin P
In the given figure, PQR is a triangle, in which QS ⊥ PR, QS = 3 cm, PS = 4 cm and QR = 12 cm, find the value of: cot2P - cosec2P
In the given figure, PQR is a triangle, in which QS ⊥ PR, QS = 3 cm, PS = 4 cm and QR = 12 cm, find the value of: 4sin2R - `(1)/("tan"^2"P")`
In an isosceles triangle ABC, AB = BC = 6 cm and ∠B = 90°. Find the values of cos C
In an isosceles triangle ABC, AB = BC = 6 cm and ∠B = 90°. Find the values of cosec C
In an isosceles triangle ABC, AB = BC = 6 cm and ∠B = 90°. Find the values of cos2 C + cosec2 C
In the given figure, AD is the median on BC from A. If AD = 8 cm and BC = 12 cm, find the value of sin x
In the given figure, AD is the median on BC from A. If AD = 8 cm and BC = 12 cm, find the value of cos y
In the given figure, AD is the median on BC from A. If AD = 8 cm and BC = 12 cm, find the value of tan x. cot y
In the given figure, AD is the median on BC from A. If AD = 8 cm and BC = 12 cm, find the value of `(1)/("sin"^2 x) - (1)/("tan"^2 x)`
In a right-angled triangle PQR, ∠PQR = 90°, QS ⊥ PR and tan R =`(5)/(12)`, find the value of sin ∠PQS
In a right-angled triangle PQR, ∠PQR = 90°, QS ⊥ PR and tan R =`(5)/(12)`, find the value of tan ∠SQR
In the given figure, ΔABC is right angled at B.AD divides BC in the ratio 1 : 2. Find
(i) `("tan"∠"BAC")/("tan"∠"BAD")` (ii) `("cot"∠"BAC")/("cot"∠"BAD")`
If sin A = `(7)/(25)`, find the value of : `(2"tanA")/"cot A - sin A"`
If sin A = `(7)/(25)`, find the value of : `"cos A" + (1)/"cot A"`
If sin A = `(7)/(25)`, find the value of : cot2A - cosec2A
If cosec θ = `(29)/(20)`, find the value of: cosec θ - `(1)/("cot" θ)`
If cosec θ = `(29)/(20)`, find the value of: `("sec" θ)/("tan" θ - "cosec" θ)`
In the given figure, AC = 13cm, BC = 12 cm and ∠B = 90°. Without using tables, find the values of: sin A cos A
In the given figure, AC = 13cm, BC = 12 cm and ∠B = 90°. Without using tables, find the values of: `("cos A" - "sin A")/("cos A" + "sin A")`
In tan θ = 1, find the value of 5cot2θ + sin2θ - 1.
In the given figure, ∠Q = 90°, PS is a median om QR from P, and RT divides PQ in the ratio 1 : 2. Find: `("tan" ∠"PSQ")/("tan"∠"PRQ")`
In the given figure, ∠Q = 90°, PS is a median om QR from P, and RT divides PQ in the ratio 1 : 2. Find: `("tan" ∠"TSQ")/("tan"∠"PRQ")`
In the given figure, AD is perpendicular to BC. Find: 5 cos x
In the given figure, AD is perpendicular to BC. Find: 15 tan y
In the given figure, AD is perpendicular to BC. Find: 5 cos x - 12 sin y + tan x
In the given figure, AD is perpendicular to BC. Find:
`(3)/("sin" x) + (4)/("cos" y) - 4 "tan" y`
In a right-angled triangle ABC, ∠B = 90°, BD = 3, DC = 4, and AC = 13. A point D is inside the triangle such as ∠BDC = 90°.
Find the values of 2 tan ∠BAC - sin ∠BCD
In a right-angled triangle ABC, ∠B = 90°, BD = 3, DC = 4, and AC = 13. A point D is inside the triangle such as ∠BDC = 90°.
Find the values of 3 - 2 cos ∠BAC + 3 cot ∠BCD
If 24cosθ = 7 sinθ, find sinθ + cosθ.
If 4 sinθ = 3 cosθ, find tan2θ + cot2θ
If 4 sinθ = 3 cosθ, find `(6sinθ - 2cosθ )/(6sinθ + 2cosθ )`
If 8tanA = 15, find sinA - cosA.
If 3cosθ - 4sinθ = 2cosθ + sinθ, find tanθ.
If 5cosθ = 3, find the value of `(4cosθ - sinθ)/(2cosθ + sinθ)`
If 4sinθ = `sqrt(13)`, find the value of `(4sinθ - 3cosθ)/(2sinθ + 6cosθ)`
If 4sinθ = `sqrt(13)`, find the value of 4sin3θ - 3sinθ
If 5tanθ = 12, find the value of `(2sinθ - 3cosθ)/(4sinθ - 9cosθ)`.
If 35 sec θ = 37, find the value of sin θ - sin θ tan θ.
If cotθ = `(1)/sqrt(3)`, show that `(1 - cos^2θ)/(2 - sin^2θ) = (3)/(5)`
If cosecθ = `1(9)/(20)`, show that `(1 - sinθ + cosθ)/(1 + sinθ + cosθ) = (3)/(7)`
If b tanθ = a, find the values of `(cosθ + sinθ)/(cosθ - sinθ)`.
If a cotθ = b, prove that `("a"sinθ - "b"cosθ)/("a"sinθ + "b"cosθ) = ("a"^2 - "b"^2)/("a"^2 + "b"^2)`
If cotθ = `sqrt(7)`, show that `("cosec"^2θ -sec^2θ)/("cosec"^2θ + sec^2θ) = (3)/(4)`
If 12cosecθ = 13, find the value of `(sin^2θ - cos^2θ) /(2sinθ cosθ) xx (1)/tan^2θ`.
If 12 cotθ = 13, find the value of `(2sinθ cosθ)/(cos^2θ - sin^2θ)`.
If secA = `(5)/(4)`, cerify that `(3sin"A" - 4sin^3"A")/(4cos^3"A" - 3cos"A") = (3tan"A" - tan^3"A")/(1 - 3tan^2"A")`.
If sinθ = `(3)/(4)`, prove that `sqrt(("cosec"^2θ - cot^2θ)/(sec^2θ - 1)) = sqrt(7)/(3)`.
If secA = `(17)/(8)`, verify that `(3 - 4sin^2 "A")/(4 cos^2 "A" - 3)= (3 - tan^2"A")/(1 - 3tan^2"A")`
If 3 tanθ = 4, prove that `sqrt(secθ - "cosec"θ)/(sqrt(secθ - "cosec"θ)) = (1)/sqrt(7)`.
If tan θ = `"m"/"n"`, show that `"m sin θ - n cos θ"/"m sinθ + n cos θ" = ("m"^2 - "n"^2)/("m"^2 + "n"^2)`
Solutions for 26: Trigonometrical Ratios
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Frank solutions for Mathematics [English] Class 9 ICSE chapter 26 - Trigonometrical Ratios
Shaalaa.com has the CISCE Mathematics Mathematics [English] Class 9 ICSE CISCE solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. Frank solutions for Mathematics Mathematics [English] Class 9 ICSE CISCE 26 (Trigonometrical Ratios) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.
Further, we at Shaalaa.com provide such solutions so students can prepare for written exams. Frank textbook solutions can be a core help for self-study and provide excellent self-help guidance for students.
Concepts covered in Mathematics [English] Class 9 ICSE chapter 26 Trigonometrical Ratios are Concept of Perpendicular, Base, and Hypotenuse in a Right Triangle, Notation of Angles, Trigonometric Ratios and Its Reciprocal, Reciprocal Relations.
Using Frank Mathematics [English] Class 9 ICSE solutions Trigonometrical Ratios exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in Frank Solutions are essential questions that can be asked in the final exam. Maximum CISCE Mathematics [English] Class 9 ICSE students prefer Frank Textbook Solutions to score more in exams.
Get the free view of Chapter 26, Trigonometrical Ratios Mathematics [English] Class 9 ICSE additional questions for Mathematics Mathematics [English] Class 9 ICSE CISCE, and you can use Shaalaa.com to keep it handy for your exam preparation.