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In the given figure, ∠Q = 90°, PS is a median om QR from P, and RT divides PQ in the ratio 1 : 2. Find: tan ∠ PSQ tan ∠ PRQ - Mathematics

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प्रश्न

In the given figure, ∠Q = 90°, PS is a median om QR from P, and RT divides PQ in the ratio 1 : 2. Find: `("tan" ∠"PSQ")/("tan"∠"PRQ")`

योग

उत्तर

As PS is the median on QR from P.
∴ QS = SR
⇒ QR = 2QS
and RT divides PQ in the ratio 1 : 2
∴ QT = x and PT = 2x
⇒  PQ = 3x

`("tan" ∠"PSQ")/("tan"∠"PRQ")`

= `("PQ"/"QS")/("PQ"/"QR")`

= `"PQ"/"QS" xx "QR"/"PQ"`

= `(2"QS")/("QS")`
= 2.

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अध्याय 26: Trigonometrical Ratios - Exercise 26.1

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फ्रैंक Mathematics [English] Class 9 ICSE
अध्याय 26 Trigonometrical Ratios
Exercise 26.1 | Q 19.1
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