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प्रश्न
In the given figure, AD is perpendicular to BC. Find: 5 cos x
उत्तर
ΔADB is a right-angled triangle.
∴ AB2
= AB2 + BD2
= 122 + 162
= 144 + 256
= 400
⇒ AB = 20cm
ΔADC is a right-angled triangle.
∴ AC2
= AD2 + DC2
= 122 + 92
= 144 + 81
= 225
⇒ AC = 15cm
5 cos x
= `5 xx "BD"/"AB"`
= `5 xx (16)/(20)`
= 4.
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