Advertisements
Advertisements
प्रश्न
In a basket there are 10 tomatoes. The weight of each of these tomatoes in grams is as follows:
60, 70, 90, 95, 50, 65, 70, 80, 85, 95.
Find the median of the weights of tomatoes.
उत्तर
The weight of 10 tomatoes in a basket in grams in ascending order is as follows:
50, 60, 65, 70, 70, 80, 85, 90, 95, 95
Since, the number of observations is 10, which is even.
So, median
= `1/2 xx [(10 / 2)^"th" "observation" + ( 10/2 +1)^"th" "observation"]`
= `1/2 xx [5^"th" "observation" + ( 5 + 1)^"th" "observation"]`
= `1/2 xx [5^"th" "observation" + 6^"th" "observation"]`
= `1/2 xx [70 +80]`
= `150/2`
= 75
The median of the weights of tomatoes is 75 grams.
APPEARS IN
संबंधित प्रश्न
Calculate the mean of the distribution given below using the shortcut method.
| Marks | 11-20 | 21-30 | 31-40 | 41-50 | 51-60 | 61-70 | 71-80 |
| No. of students | 2 | 6 | 10 | 12 | 9 | 7 | 4 |
Find the mode and the median of the following frequency distribution:
| x | 10 | 11 | 12 | 13 | 14 | 15 |
| f | 1 | 4 | 7 | 5 | 9 | 3 |
Attempt this question on a graph paper. The table shows the distribution of marks gained by a group of 400 students in an examination.
|
Marks (Less than ) |
10 | 20 | 30 | 40 | 50 | 60 | 70 | 80 | 90 | 100 |
| No.of student | 5 | 10 | 30 | 60 | 105 | 180 | 270 | 355 | 390 | 400 |
Using scaie of 2cm to represent 10 marks and 2 cm to represent 50 student, plot these point and draw a smooth curve though the point
Estimate from the graph :
(1)the median marks
(2)the quartile marks.
Find the mean of the following frequency distribution :
| Class | 1-10 | 11-20 | 21-30 | 31-40 | 41-50 |
| Frequency | 9 | 12 | 15 | 10 | 14 |
Find the rnedian of the first 15 whole numbers .
The marks obtained by 200 students in an examination are given below :
| Marks | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 | 60-70 | 70-80 | 80-90 | 90-100 |
| No.of students | 5 | 10 | 11 | 20 | 27 | 38 | 40 | 29 | 14 | 6 |
Using a graph paper, draw an Ogive for the above distribution. Use your Ogive to estimate:
(i) the median;
(ii) the lower quartile;
(iii) the number of students who obtained more than 80% marks in the examination and
(iv) the number of students who did not pass, if the pass percentage was 35.
Use the scale as 2 cm = 10 marks on one axis and 2 cm = 20 students on the other axis.
The mean of a certain number of observations is 32. Find the resulting mean, if the observation is decreased by 20%.
Find the median of the following sets of numbers.
15, 8, 14, 20, 13, 12, 16
Find the median of the given values : 47, 53, 62, 71, 83, 21, 43, 47, 41
Find the median of the 10 observations 36, 33, 45, 28, 39, 45, 54, 23, 56, 25. If another observation 35 is added to the above data, what would be the new median?
