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In fig., seg AC and seg BD intersect each other at point P. APPCBPPDAPPC=BPPD then prove that ΔABP ~ ΔCDP - Geometry Mathematics 2

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प्रश्न

In fig., seg AC and seg BD intersect each other at point P.


APPC=BPPD then prove that ΔABP ~ ΔCDP

योग

उत्तर

In ΔABP and ΔCDP,

APPC=BPPD    ......[Given]

∠APB ≅ ∠CPD     .......[Vertically opposite angles]

∴ ΔABP ~ ΔCDP   .......[SAS test of similarity]

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 1: Similarity - Q.2 (B)

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