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TridefTrimnk. If De = 5 and Mn = 6, Then Find the Value of A(Tridef)A(Trimnk) - Geometry Mathematics 2

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प्रश्न

DEFMNK. If DE = 5 and MN = 6, then find the value of A(DEF)A(MNK)

उत्तर

A(DEF)A(MNK) = (DE)2(MN)2=2536 (Ratio of areas of similar triangles is equal to squares of corresponding sides)

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2017-2018 (March) Set A

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