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The Areas of Two Similar Triangles Are `64cm^2` and `100cm^2` Respectively. If a Median of the Smaller Triangle is 5.6cm, Find the Corresponding Median of the Other. - Mathematics

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प्रश्न

The areas of two similar triangles are `64cm^2` and `100cm^2` respectively. If a median of the smaller triangle is 5.6cm, find the corresponding median of the other. 

उत्तर

Let the two triangles be ABC and PQR with medians AM and PN, respectively. 

 Therefore, the ratio of areas of two similar triangles will be equal to the ratio of squares of their corresponding medians. 

∴ `(ar(ΔABC))/(ar(ΔPQR))=(AM^2)/(PN^2)` 

⇒ `64/100=5.6^2/(PN^2` 

⇒ `PN^2=64/100xx5.6^2` 

⇒ `PN^2= sqrt(100/64xx5.6xx5.6)` 

= 7 cm
Hence, the median of the larger triangle is 7 cm. 

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अध्याय 4: Triangles - Exercises 3

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आरएस अग्रवाल Mathematics [English] Class 10
अध्याय 4 Triangles
Exercises 3 | Q 8

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