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प्रश्न
In the following figure, in Δ PQR, seg RS is the bisector of ∠PRQ.
PS = 3, SQ = 9, PR = 18. Find QR.
उत्तर
SR is the bisector of ∠R.
`"RP"/"PS"="QR"/"SQ"`
`rArr18/3="QR"/9`
`therefore"QR"=54"cm"`
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