Advertisements
Advertisements
प्रश्न
In ΔPQR, PS is a median. T is the mid-point of SR and M is the mid-point of PT. Prove that: ΔPMR = `(1)/(8)Δ"PQR"`.
उत्तर
Area(ΔPQR) = area(ΔPQS) + area(ΔPSR) ....(i)
Since PS is the median of ΔPQR and median divides a triangle into two triangles of equal area.
Therefore, area(ΔPQS) = area(ΔPSR)
Substituting in (i)
Area(ΔPQR) = area(ΔPSR) + area(ΔPSR)
Area(ΔPQR) = 2area(ΔPSR) .........(iii)
Area(ΔPSR) = area(ΔPST) + area(ΔPTR) .....(iv)
Since PT is the median of ΔPSR and median divides a triangle into triangles of equal area.
Therefore, area(ΔPST) = area(ΔPTR) .....(v)
Substituting in (v)
Area(ΔPSR) = 2area(ΔPTR) ........(vi)
Substituting in (iii)
Area(ΔPQR) = 2 x 2area(ΔPTR)
Area(ΔPQR) = 4area(ΔPTR) .........(vii)
Area(ΔPQR) = area(ΔPMR) + area(ΔMTR) .....(viii)
Since MR is the median of ΔPTR and median divides a triangle into two triangles of equal area.
Therefore, area(ΔPMR) = area(ΔMTR) ....(ix)
Substituting in (viii)
Area(ΔPQR) = 4 x 2area(ΔPMR)
Area(ΔPQR) = 8 x area(ΔPMR)
area(ΔPMR) = `(1)/(8)"area(ΔPQR)"`.
APPEARS IN
संबंधित प्रश्न
ABCD is a parallelogram. P and Q are mid-points of AB and CD. Prove that APCQ is also a parallelogram.
SN and QM are perpendiculars to the diagonal PR of parallelogram PQRS.
Prove that:
(i) ΔSNR ≅ ΔQMP
(ii) SN = QM
PQRS is a parallelogram. PQ is produced to T so that PQ = QT. Prove that PQ = QT. Prove that ST bisects QR.
ABCD is a rectangle with ∠ADB = 55°, calculate ∠ABD.
P is a point on side KN of a parallelogram KLMN such that KP : PN is 1 : 2. Q is a point on side LM such that LQ : MQ is 2 : 1. Prove that KQMP is a parallelogram.
Prove that the line segment joining the mid-points of the diagonals of a trapezium is parallel to each of the parallel sides, and is equal to half the difference of these sides.
ABCD is a trapezium in which side AB is parallel to side DC. P is the mid-point of side AD. IF Q is a point on the Side BC such that the segment PQ is parallel to DC, prove that PQ = `(1)/(2)("AB" + "DC")`.
Prove that the diagonals of a parallelogram divide it into four triangles of equal area.
PQRS is a parallelogram and O is any point in its interior. Prove that: area(ΔPOQ) + area(ΔROS) - area(ΔQOR) + area(ΔSOP) = `(1)/(2)`area(|| gm PQRS)
In the given figure, PQ ∥ SR ∥ MN, PS ∥ QM and SM ∥ PN. Prove that: ar. (SMNT) = ar. (PQRS).