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In δPqr, Ps is a Median. T is the Mid-point of Sr and M is the Mid-point of Pt. Prove That: δPmr = 1 8 δ Pqr - Mathematics

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प्रश्न

In ΔPQR, PS is a median. T is the mid-point of SR and M is the mid-point of PT. Prove that: ΔPMR = `(1)/(8)Δ"PQR"`.

योग

उत्तर

Area(ΔPQR) = area(ΔPQS) + area(ΔPSR) ....(i)
Since PS is the median of ΔPQR and median divides a triangle into two triangles of equal area.
Therefore, area(ΔPQS) = area(ΔPSR)
Substituting in (i)
Area(ΔPQR) = area(ΔPSR) + area(ΔPSR)
Area(ΔPQR) = 2area(ΔPSR) .........(iii)
Area(ΔPSR) = area(ΔPST) + area(ΔPTR) .....(iv)
Since PT is the median of ΔPSR and median divides a triangle into triangles of equal area.
Therefore, area(ΔPST) = area(ΔPTR)  .....(v)
Substituting in (v)
Area(ΔPSR) = 2area(ΔPTR) ........(vi)
Substituting in (iii)
Area(ΔPQR) = 2 x 2area(ΔPTR)
Area(ΔPQR) = 4area(ΔPTR) .........(vii)
Area(ΔPQR) = area(ΔPMR) + area(ΔMTR) .....(viii)
Since MR is the median of ΔPTR and median divides a triangle into two triangles of equal area.
Therefore, area(ΔPMR) = area(ΔMTR)  ....(ix)
Substituting in (viii)
Area(ΔPQR) = 4 x 2area(ΔPMR)
Area(ΔPQR) = 8 x area(ΔPMR)

area(ΔPMR) = `(1)/(8)"area(ΔPQR)"`.

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Diagonal Properties of Different Kinds of Parallelograms
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 21: Areas Theorems on Parallelograms - Exercise 21.1

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फ्रैंक Mathematics [English] Class 9 ICSE
अध्याय 21 Areas Theorems on Parallelograms
Exercise 21.1 | Q 31
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