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In Quadrilateral ABCD, side AD || BC, diagonal AC and BD intersect in point P, then prove that APPDPCBPAPPD=PCBP - Geometry Mathematics 2

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प्रश्न

In Quadrilateral ABCD, side AD || BC, diagonal AC and BD intersect in point P, then prove that `"AP"/"PD" = "PC"/"BP"`

योग

उत्तर

Proof: seg AD || seg BC and BD is their transversal.    ...[Given]

∴ ∠DBC ≅ ∠BDA     ...[Alternate angles]

∴ ∠PBC ≅ ∠PDA      ...(i)[D−P−B]

In ΔPBC and ΔPDA,

∠PBC ≅ ∠PDA   ...[From (i)]

∠BPC ≅ ∠DPA   ...[Vertically opposite angles]

∴ ΔPBC ∼ ΔPDA    ...[AA test of similarity]

∴ `"BP"/"PD" = "PC"/"AP"`    ...[Corresponding sides of similar triangles]

∴ `"AP"/"PD" = "PC"/"BP"`   ...[By alternendo]

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अध्याय 1: Similarity - Q.3 (B)

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