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प्रश्न
In the given figure, T is a point on the side PR of an equilateral triangle PQR. Show that RT < QT
उत्तर
In ΔPQR,
PQ = QR = PR
⇒ ∠P = Q = ∠ = 60°
In ΔTQR,
∠TQR < 60°
∴ ∠TQR < ∠R
∴ RT < QT.
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