Advertisements
Advertisements
प्रश्न
In ΔPQR, PS ⊥ QR ; prove that: PQ > QS and PQ > PS
उत्तर
In ΔPQS,
PS < PQ ....(Of all the straight lines that can be drawn to a given straight line from a point outside it, the perpendicular is the shortest.)
I.e. PQ > PS
Also, QS < QP ....(Of all the straight lines that can be drawn to a given straight line from a point outside it, the perpendicular is the shortest.)
i.e. PQ > QS.
APPEARS IN
संबंधित प्रश्न
ABC is a triangle. Locate a point in the interior of ΔABC which is equidistant from all the vertices of ΔABC.
In a triangle locate a point in its interior which is equidistant from all the sides of the triangle.
In a huge park people are concentrated at three points (see the given figure):
A: where there are different slides and swings for children,
B: near which a man-made lake is situated,
C: which is near to a large parking and exit.
Where should an ice-cream parlour be set up so that maximum number of persons can approach it?
(Hint: The parlor should be equidistant from A, B and C)
From the following figure, prove that: AB > CD.
If two sides of a triangle are 8 cm and 13 cm, then the length of the third side is between a cm and b cm. Find the values of a and b such that a is less than b.
In the following figure, write BC, AC, and CD in ascending order of their lengths.
D is a point in side BC of triangle ABC. If AD > AC, show that AB > AC.
D is a point on the side of the BC of ΔABC. Prove that the perimeter of ΔABC is greater than twice of AD.
ABCD is a quadrilateral in which the diagonals AC and BD intersect at O. Prove that AB + BC + CD + AD < 2(AC + BC).
In the given figure, T is a point on the side PR of an equilateral triangle PQR. Show that PT < QT
