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Question
In ΔPQR, PS ⊥ QR ; prove that: PQ > QS and PQ > PS
Solution
In ΔPQS,
PS < PQ ....(Of all the straight lines that can be drawn to a given straight line from a point outside it, the perpendicular is the shortest.)
I.e. PQ > PS
Also, QS < QP ....(Of all the straight lines that can be drawn to a given straight line from a point outside it, the perpendicular is the shortest.)
i.e. PQ > QS.
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