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प्रश्न
Integrate the function:
f' (ax + b) [f (ax + b)]n
उत्तर
Let = ∫ f'(ax + b).[f(ax + b)]n dx
Put f(ax + b) = t
∴af'(ax + b) dx = dt
∴ `I = 1/a int t^n dt = 1/a (t^(n + 1))/(n + 1) + C`
`= 1/((n + 1)a) [f (ax + b)]^(n + 1) + C`
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