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Let A = (1, 0),(2, 1), B = (2, 3),(-1, 0). Find A^2 + Ab + B^2 - Mathematics

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प्रश्न

Let `A = [(1, 0),(2, 1)], B = [(2, 3),(-1, 0)]`. Find `A^2 + AB + B^2`

योग

उत्तर

`A = [(1, 0),(2, 1)], B = [(2, 3),(-1, 0)]`

`A^2 = A xx A = [(1, 0),(2, 1)] xx [(1, 0),(2, 1)]`

`=[(1 xx 1 + 0 xx 2, 1 xx 0 + 0 xx 1),(2 xx 1 + 1 xx 2, 2 xx 0 + 1 xx 1)] = [(1, 0),(4, 1)]`

`AB = A xx B = [(1, 0),(2, 1)] xx [(2, 3),(-1, 0)]`

`=[(1 xx 2 + 0 xx (-1), 1 xx 3 + 0 xx 0),(2 xx 2 + 1 xx (-1), 2 xx 3 + 1 xx 0)]`

`= [(2, 3),(3, 6)]`

`B^2 = B  xx  B = [(2, 3),(-1, 0)] xx [(2, 3),(-1, 0)]`

`= [(2 xx 2 + 3 xx (-1), 2 xx 3 + 3 xx 0),((-1)xx2 + 0 xx (-1), -1 xx 3 + 0 xx 0)]`

`= [(1, 6),(-2, -3)]`

`:. A^2 + AB + B^2 = [(1, 0),(4, 1)] + [(2, 3),(3, 6)] + [(1, 6),(-2, -3)]`

`= [(4, 9),(5, 4)]`

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अध्याय 9: Matrices - Exercise 9 (D) [पृष्ठ १३२]

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सेलिना Mathematics [English] Class 10 ICSE
अध्याय 9 Matrices
Exercise 9 (D) | Q 16 | पृष्ठ १३२

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