Advertisements
Advertisements
प्रश्न
Let Δ ABC ~ Δ DEF and their areas be, respectively, 64 cm2 and 121 cm2. If EF = 15.4 cm, find BC
उत्तर
It is given that ΔABC ~ ΔDEF
`:. (ar(triangleABC))/(ar(triangleDEF)) = ((AB)/(DE))^2 = ((BC)/(EF))^2=((AC)/(DF))^2`
Given that
EF = 15.4
ar(ΔABC) = 64 cm2
ar(ΔDEF) = 121 cm2
`:.(ar(ABC))/(ar(ΔDEF))=((BC)/(EF))^2`
`=>((64 cm^2)/(121 cm^2)) = (BC^2)/(15.4 cm)^2`
`=>(BC)/15.4 = (8/11)cm`
`=>BC = ((8xx15.4)/11)cm = (8 xx 1.4) cm = 11.2 cm`
APPEARS IN
संबंधित प्रश्न
Prove that the area of the triangle BCE described on one side BC of a square ABCD as base is one half the area of the similar Triangle ACF described on the diagonal AC as base
Prove that the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding medians.
Triangles ABC and DEF are similar If AC = 19cm and DF = 8 cm, find the ratio of the area of two triangles.
Two isosceles triangles have equal vertical angles and their areas are in the ratio 36 : 25. Find the ratio of their corresponding heights.
The areas of two similar triangles are 25 cm2 and 36 cm2 respectively. If the altitude of the first triangle is 2.4 cm, find the corresponding altitude of the other.
The corresponding altitudes of two similar triangles are 6 cm and 9 cm respectively. Find the ratio of their areas.
If ∆ABC ~ ∆PQR, A (∆ABC) = 80, A (∆PQR) = 125, then fill in the blanks. \[\frac{A\left( ∆ ABC \right)}{A\left( ∆ . . . . \right)} = \frac{80}{125} \therefore \frac{AB}{PQ} = \frac{......}{......}\]
If ΔABC is similar to ΔDEF such that 2 AB = DE and BC = 8 cm then EF is equal to ______.
If ΔABC ~ ΔPQR, AB : PQ = 4 : 5 and A(ΔPQR) = 125 cm2, then find A(ΔABC).
If the perimeter of two similar triangles is in the ratio 2 : 3, what is the ratio of their sides?
