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Mark the Correct Alternative in the Following Question:For the Following Probability Distribution:X:−4−3−2−10p(X):0.10.20.30.20.2the Value of E(X) Is - Mathematics

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प्रश्न

Mark the correct alternative in the following question:
For the following probability distribution:

X: −4 −3 −2 −1 0
P(X): 0.1 0.2 0.3 0.2 0.2

The value of E(X) is

 

 

विकल्प

  • 0  

  • −1 

  • −2 

  • −1.8

MCQ

उत्तर

The probability distribution of X is given below:
 

X: −4 −3 −2 −1 0
P(X): 0.1 0.2 0.3 0.2 0.2

\[E\left( X \right) = \left( - 4 \right) \times 0 . 1 + \left( - 3 \right) \times 0 . 2 + \left( - 2 \right) \times 0 . 3 + \left( - 1 \right) \times 0 . 2 + 0 \times 0 . 2\]
\[ = - 0 . 4 - 0 . 6 - 0 . 6 - 0 . 2\]
\[ = - 1 . 8\]

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अध्याय 32: Mean and Variance of a Random Variable - MCQ [पृष्ठ ४७]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 32 Mean and Variance of a Random Variable
MCQ | Q 7 | पृष्ठ ४७

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