Advertisements
Advertisements
प्रश्न
Prove that sin 48° sec 42° + cos 48° cosec 42° = 2
उत्तर
We will simplify the left-hand side
`sin 48° sec 42° + cos 48° cosec 42° = sin 48^@. sec(90^@ - 48^@) + cos 48^@ cosec (90^@ - 48^@)`
`= sin 48^@. sec 48^@ + cos 48^@. cosec 42^@ = sin 48^@ . sec(90^@ - 48^@) + cos 48^@.cosec (90^@ - 48^@)`
`= sin 48^@.cos 48^@ + cos 48^@. sin 48^@`
= 1 + 1
= 2
Proved
APPEARS IN
संबंधित प्रश्न
Evaluate the following :
`tan 35^@/cot 55^@ + cot 78^@/tan 12^@ -1`
Evaluate: tan 7° tan 23° tan 60° tan 67° tan 83°
Prove that
tan (55° − θ) − cot (35° + θ) = 0
If A = 30°;
show that:
sin 3 A = 4 sin A sin (60° - A) sin (60° + A)
find the value of: cos2 60° + sin2 30°
Prove that:
cos2 30° - sin2 30° = cos 60°
secθ . Cot θ= cosecθ ; write true or false
If `sqrt3` = 1.732, find (correct to two decimal place) the value of `(2)/(tan 30°)`
Without using tables, evaluate the following: sin230° sin245° + sin260° sin290°.
The value of 5 sin2 90° – 2 cos2 0° is ______.
