Advertisements
Advertisements
प्रश्न
Rationalize the denominator.
`5/sqrt 7`
योग
उत्तर
`5/sqrt 7`
`= 5/sqrt 7 xx sqrt 7/ sqrt 7`
`= (5 sqrt 7)/(sqrt 7)^2 `
`= (5 sqrt 7)/7`
shaalaa.com
Rationalisation of Surds
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 2: Real Numbers - Practice Set 2.3 [पृष्ठ ३०]
APPEARS IN
संबंधित प्रश्न
Rationalize the denominator.
`11 / sqrt 3`
Write the simplest form of rationalising factor for the given surd.
`3/5 sqrt 10`
Write the lowest rationalising factor of √5 - 3.
Write the lowest rationalising factor of : 7 - √7
Write the lowest rationalising factor of : √5 - √2
Write the lowest rationalising factor of : 15 - 3√2
If x =`[sqrt5 - 2 ]/[ sqrt5 + 2]` and y = `[ sqrt5 + 2]/[ sqrt5 - 2 ]`; find :
x2
If x = 5 - 2√6, find `x^2 + 1/x^2`
Rationalise the denominator `sqrt(75)/sqrt(18)`
Rationalise the denominator and simplify `(2sqrt(6) - sqrt(5))/(3sqrt(5) - 2sqrt(6))`
