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प्रश्न
Show that `sin^-1 5/13 + cos^-1 3/5 = tan^-1 63/16`
उत्तर
`sin^-1 5/13 = tan^-1 5/12`
`cos^-1 3/5 = tan^-1 4/3`
∴ L.H.S. = `sin^-1 5/13 + cos^-1 3/5`
= `tan^-1 5/12 + tan^-1 4/3`
= `tan-1 (5/12 + 4/3)/(1 - 5/12 * 4/3)`
= `tan^-1 ((15 + 48)/36)/((36 - 20)/36)`
= `tan^-1 63/16`
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