22x+1= 8⇒ 22x+1= 23⇒ 2x + 1 = 3⇒ 2x = 2⇒ x = 1.

Solve for X: 22x+1= 8 - Mathematics

Solve for x:
2^2x+1= 8

योग

2^2x+1= 8
⇒ 2^2x+1= 2³
⇒ 2x + 1 = 3
⇒ 2x = 2
⇒ x = 1.

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Solving Exponential Equations

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अध्याय 9: Indices - Exercise 9.1

अध्याय 9 Indices
Exercise 9.1 | Q 9.01

Find x, if : `sqrt( 2^( x + 3 )) = 16`

Find x, if : `(root(3)( 2/3))^( x - 1 ) = 27/8`

If 4^{x + 3} = 112 + 8 × 4^x, find the value of (18x)^3x.

If 5^{x + 1} = 25^{x - 2}, find the value of 3^{x - 3} × 2^{3 - x}.

Find the values of m and n if :
`4^(2m) = ( root(3)(16))^(-6/n) = (sqrt8)^2`

Evaluate the following:

`(27)^(2/3) xx 8^((-1)/6) ÷ 18^((-1)/2)`

Solve for x:
2^{x + 3} + 2^{x + 1} = 320

Solve for x:
5^x2 : 5^x= 25 : 1

If 2^x = 3^y = 12^z ; show that `(1)/z = (1)/y + (2)/x`.

Prove the following:

`sqrt(x^-1 y) · sqrt(y^-1 z) · sqrt(z^-1 x)` = 1