22x+1= 8⇒ 22x+1= 23⇒ 2x + 1 = 3⇒ 2x = 2⇒ x = 1.

Solve for X: 22x+1= 8 - Mathematics

Solve for x:
2^2x+1= 8

बेरीज

2^2x+1= 8
⇒ 2^2x+1= 2³
⇒ 2x + 1 = 3
⇒ 2x = 2
⇒ x = 1.

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Solving Exponential Equations

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पाठ 9: Indices - Exercise 9.1

पाठ 9 Indices
Exercise 9.1 | Q 9.01

Find x, if : `( sqrt(3/5))^( x + 1) = 125/27`

Solve : 2^2x + 2^x+2 - 4 x 2³ = 0

Solve for x:

`2^(3x + 3) = 2^(3x + 1) + 48`

Find the values of m and n if :
`4^(2m) = ( root(3)(16))^(-6/n) = (sqrt8)^2`

Solve x and y if : ( √32 )^x ÷ 2^{y + 1} = 1 and 8^y - 16^{4 - x/2} = 0

Evaluate the following:

`16^(3/4) + 2(1/2)^-1 xx 3^0`

Solve for x:
2^2x + 2^{x +2} - 4 x 2³ = 0

Solve for x:
5^x2 : 5^x= 25 : 1

Solve for x:
9^x+4= 3² x (27)^x+1

If a^x = b^y = c^z and abc = 1, show that

`(1)/x + (1)/y + (1)/z` = 0.