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प्रश्न
Solve the following quadratic equation using formula:
x2 + 10x + 2 = 0
उत्तर
x2 + 10x + 2 = 0, comparing with ax2 + bx + c = 0
We get, a = 1, b = 10, c = 2
∴ b2 – 4ac = (10)2 – 4 × 1 × 2
= 100 – 8
= 92
∵ x = `(-b +- sqrt(b^2 - 4ac))/(2a)`
∴ x = `(-10 +- sqrt(92))/(2 xx 1)`
∴ x = `(-10 +- sqrt(23 xx 4))/2`
∴ x = `(-10 +- 2sqrt(23))/2`
∴ x = `(2(-5 +- sqrt(23)))/2`
∴ x = `-5 + sqrt(23)` or x = `- 5 - sqrt(23)`
∴ Roots of the quadratic equation are `-5 + sqrt(23)` or `-5 - sqrt(23)`
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