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प्रश्न
The following table gives the distribution of IQ's (intelligence quotients) of 60 pupils of class V in a school:
IQ's: | 125.5 to 13.25 |
118.5 to 125.5 |
111.5 to 118.5 |
104.5 to 111.5 |
97.5 to 104.5 |
90.5 to 97.5 |
83.5 to 90.5 |
76.5 to 83.5 |
69.5 to 76.5 |
62.5 to 69.5 |
No. of pupils: |
1 | 3 | 4 | 6 | 10 | 12 | 15 | 5 | 3 | 1 |
Draw a frequency polygon for the above data.
उत्तर १
We first draw horizontal and vertical axes. Let us consider that the horizontal and vertical axes represent the class-limits and the frequencies of the class-intervals respectively.
The given data is a continuous grouped frequency distribution with equal class-intervals. To draw the frequency polygon of the given data without using histogram, obtain the class-limits of the class intervals. Obtain the class-limits of two class-intervals of 0 frequencies, i.e. on the horizontal axis, one adjacent to the first, on its left and one adjacent to the last, on its right. These class-intervals are known as imagined class-intervals. Then plot the frequencies against class-limits.
The following table is useful to draw the frequency polygon of the given data.
Class - Intervals | Class - Marks | Frequency |
55.5-62.5 | 59 | 0 |
62.5-69.5 | ||
We represent class marks on X-axis on a suitable scale and the frequencies on Y-axis on a suitable scale.
To obtain the frequency polygon we plot the points (66, 1), (73, 3), (80, 5), (87, 15), (94, 12), (101, 10), (108, 6), (115, 4), (122, 3), (129, 1).
Now we join the plotted points by line segments. The end points (66, 1) and (129, 1) are joined to the mid points (59, 0) and ( 136, 0) respectively of imagined class intervals to obtain the frequency polygon.
उत्तर २
We first draw horizontal and vertical axes. Let us consider that the horizontal and vertical axes represent the class-limits and the frequencies of the class-intervals respectively.
The given data is a continuous grouped frequency distribution with equal class-intervals. To draw the frequency polygon of the given data without using histogram, obtain the class-limits of the class intervals. Obtain the class-limits of two class-intervals of 0 frequencies, i.e. on the horizontal axis, one adjacent to the first, on its left and one adjacent to the last, on its right. These class-intervals are known as imagined class-intervals. Then plot the frequencies against class-limits.
The following table is useful to draw the frequency polygon of the given data.
Class - Intervals | Class - Marks | Frequency |
55.5-62.5 | 59 | 0 |
62.5-69.5 | 66 | 1 |
69.5 - 76.5 | 73 | 3 |
76.5 - 83.5 | 80 | 5 |
83.5 - 90.5 | 87 | 15 |
90.5 - 97.5 | 94 | 12 |
97.5-104.5 | 101 | 10 |
104-111.5 | 108 | 6 |
111.5 - 118.5 | 115 | 4 |
118.5-125.5 | 122 | 3 |
125.5-132.5 | 129 | 1 |
132.5-139.5 | 136 | 0 |
We represent class marks on X-axis on a suitable scale and the frequencies on Y-axis on a suitable scale.
To obtain the frequency polygon we plot the points (66, 1), (73, 3), (80, 5), (87, 15), (94, 12), (101, 10), (108, 6), (115, 4), (122, 3), (129, 1).
Now we join the plotted points by line segments. The end points (66, 1) and (129, 1) are joined to the mid points (59, 0) and ( 136, 0) respectively of imagined class intervals to obtain the frequency polygon.
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संबंधित प्रश्न
Given below are the seats won by different political parties in the polling outcome of a state assembly elections:-
Political Party | A | B | C | D | E | F |
Seats Won | 75 | 55 | 37 | 29 | 10 | 37 |
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- Which political party won the maximum number of seats?
The length of 40 leaves of a plant are measured correct to one millimetre, and the obtained data is represented in the following table:-
Length (in mm) | Number of leaves |
118 - 126 | 3 |
127 - 135 | 5 |
136 - 144 | 9 |
145 - 153 | 12 |
154 - 162 | 5 |
163 - 171 | 4 |
172 - 180 | 2 |
- Draw a histogram to represent the given data. [Hint: First make the class intervals continuous]
- Is there any other suitable graphical representation for the same data?
- Is it correct to conclude that the maximum number of leaves are 153 mm long? Why?
The following table shows the daily production of T. V. sets in an industry for 7 days of a week:
Day | Mon | Tue | Wed | Thurs | Fri | Sat | Sun |
Number of T.V. Sets | 300 | 400 | 150 | 250 | 100 | 350 | 200 |
Represent the above information by a pictograph .
The following table shows the number of Maruti cars sold by five dealers in a particular month:
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Cars sold: | 60 | 40 | 20 | 15 | 10 |
Represent the above information by a pictograph.
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Production of oil (in lakh tonnes) |
30 | 70 | 40 | 45 | 25 |
Construct a bar graph to represent the above data so that the bars are drawn horizontally.
Draw frequency polygons for each of the following frequency distribution:
(a) using histogram
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5 -15 | 15 -25 | 25 -35 | 35 - 45 | 45-55 | 55-65 |
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The following tables show the mode of transport used by boys and girls for going to the same school.
Bus | Bicycle | Walking | Other sources | |
Number of boys |
80 | 60 | 20 | 85 |
Number of girls |
90 | 75 | 35 | 60 |
Draw a double bar graph representing the above data.
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Draw a bar graph for the above data.
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Expenditure (in Rs) |
4000 | 2500 | 1000 | 3500 | 2500 | 1500 |
Draw a bar graph to represent the data above.