Advertisements
Advertisements
प्रश्न
The point P divides the join of (2, 1) and (−3, 6) in the ratio 2 : 3. Does P lies on the line x − 5y + 15 = 0?
उत्तर
Given, the point P divides the join of (2, 1) and (−3, 6) in the ratio 2 : 3.
Co-ordinates of the point P are
`((2 xx (-3) + 3 xx 2)/(2 + 3),(2 xx 6 + 3 xx 1)/(2 + 3))`
= `((-6 + 6)/(5), (12 + 3)/(5))`
= `(0/5, 15/5)`
= (0, 3)
Substituting x = 0 and y = 3 in the given equation, we have:
L.H.S. = 0 − 5(3) + 15
= −15 + 15
= 0 = R.H.S.
Hence, the point P lies on the line x − 5y + 15 = 0.
APPEARS IN
संबंधित प्रश्न
Solve the following inequation and represent the solution set on a number line.
`-8 1/2 < -1/2 -4x <= 7 1/2`, x ∈ 1
Find the equation of a line whose : y-intercept = −1 and inclination = 45°
Find the equation of the line, whose x-intercept = −4 and y-intercept = 6
The vertices of a ΔABC are A(3, 8), B(–1, 2) and C(6, –6). Find:
(i) Slope of BC
(ii) Equation of a line perpendicular to BC and passing through A.
P is a point on the line segment AB dividing it in the ratio 2 : 3. If the coordinates of A and Bare (-2,3) and (8,8), find if Plies on the line 7x - 2y =4.
Find the value of a line parallel to the following line:
`(3"y")/4 + (5"y")/2 = 7`
Find the equation of a line passing through (2,5) and making and angle of 30° with the positive direction of the x-axis.
Find the equations of a line passing through the point (2, 3) and having the x – interecpt of 4 units.
Find the equation of the line passing through (0, 4) and parallel to the line 3x + 5y + 15 = 0.
In the given diagram, OA = OB, ∠OAB = 𝜃 and the line AB passes through point P (-3, 4).
Find:
- Slope and inclination (𝜃) of the line AB
- Equation of the line AB