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The Width of Depletion Region of P-n Junction Diode is _______. - Physics

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प्रश्न

The width of depletion region of p-n junction diode is _______.

(A) 0.5 nm to 1 nm

(B) 5 nm to 10 nm

(C) 50 nm to 500 nm

(D) 500 nm to 1000 nm

 

उत्तर

500 nm to 1000 nm

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2012-2013 (October)

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संबंधित प्रश्न

Explain with the help of a diagram, how depletion region and potential barrier are formed in a junction diode.


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(b) In what way would the use of solar panels prove to be very useful?
(c) Name the semiconductor device used in solar panels. Briefly explain with the help of a diagram, how this device works


Write briefly the important processes that occur during the formation of p−n junction. With the help of necessary diagrams, explain the term 'barrier potential'.


Draw V − I characteristics of a p-n junction diode. Answer the following questions, giving reasons:

(i) Why is the current under reverse bias almost independent of the applied potential up to a critical voltage?

(ii) Why does the reverse current show a sudden increase at the critical voltage?

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Describe briefly, with the help of a diagram, the role of the two important processes involved in the formation of a p-n junction ?


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Write the important considerations which are to be taken into account while fabricating a p-n junction diode to be used as a Light Emitting Diode (LED). What should be the order of band gap of an LED,  if it is required to emit light in the visible range? Draw a circuit diagram and explain its action. 


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Read the following paragraph and answer the questions.

LED is a heavily doped P-N junction which under forward bias emits spontaneous radiation. When it is forward-biased, due to recombination of holes and electrons at the junction, energy is released in the form of photons. In the case of Si and Ge diode, the energy released in recombination lies in the infrared region. LEDs that can emit red, yellow, orange, green and blue light are commercially available. The semiconductor used for fabrication of visible LEDs must at least have a band gap of 1.8 eV. The compound semiconductor Gallium Arsenide – Phosphide is used for making LEDs of different colours.


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    OR
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How can a photodiode be used to measure light intensity?


What energy conversion takes place in a solar cell?


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