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प्रश्न
Using the properties of determinants, solve the following for x:
`|[x+2,x+6,x-1],[x+6,x-1,x+2],[x-1,x+2,x+6]|=0`
उत्तर
`Let Delta=|[x+2,x+6,x-1],[x+6,x-1,x+2],[x-1,x+2,x+6]|`
Applying `C_2->C_2-C_1 and C_3->C_3-C_1`
`Delta=|[x+2,4,-3],[x+6,-7,-4],[x-1,3,7]|`
Applying `R_2->R_2-R_1 and R_3->R_3-R_1`
`Delta=|[x+2,4,-3],[4,-11,-1],[-3,-1,10]|`
Applying ` R_2->R_2+R_3`
`Delta=|[x+2,4,-3],[1,-12,9],[-3,-1,10]|`
Applying ` R_3->R_3+(3)R_2`
`Delta=|[x+2,4,-3],[1,-12,9],[0,-37,37]|`
Expanding along C1
`Delta=(x+2)|[-12,9],[-37,37]|-1|[4,-3],[-37,37]|`
`Delta=(x+2)(-444+333)-1(148-111)`
`Delta=(x+2)(-111)-1(37)`
`Delta=0=-111x-259`
`x=-259/111=-7/3`
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