Advertisements
Advertisements
प्रश्न
Using trigonometric table evaluate the following:
tan 78°55' - tan 55°18'
उत्तर
tan 78°55' - tan 55°18'
= 5.097 - 1.444
= 3.653.
APPEARS IN
संबंधित प्रश्न
In the below given figure, a tower AB is 20 m high and BC, its shadow on the ground, is 20√3 m long. Find the sun’s altitude.
Without using trigonometric tables, prove that:
cos 81° − sin 9° = 0
Without using trigonometric tables, prove that:
sin53° cos37° + cos53° sin37° = 1
Without using trigonometric tables, prove that:
tan48° tan23° tan42° tan67° = 1
Prove that:
`(sin 70^circ)/(cos 20^circ) + ("cosec" 20^circ)/(sec 70^circ) - 2 cos 70^circ "cosec" 20^circ = 0`
Prove that:
`cos 80^circ/(sin 10^circ) + cos 59^circ "cosec" 31^circ = 2`
Prove that:
cot12° cot38° cot52° cot60° cot78° = \[\frac{1}{\sqrt{3}}\]
If sin 3 A = cos (A − 26°), where 3 A is an acute angle, find the value of A.
Solve the following equation: `(cos^2θ - 3 cosθ + 2)/sin^2θ` = 1.
Prove that:
`(cos^2 "A")/(cos "A" - sin "A") + (sin "A")/(1 - cot "A")` = sin A + cos A
