Advertisements
Advertisements
प्रश्न
Without using trigonometric tables, prove that:
sin53° cos37° + cos53° sin37° = 1
उत्तर
LHS = sin 53° cos 37° +cos 53° sin 37°
= sin (90° - 37°) cos 37° + cos (90° - 37°) sin 37°
= cos 37° + cos 37° + sin 37° sin 37°
= cos2 37 + sin2 37
= 1
= RHS
APPEARS IN
संबंधित प्रश्न
In the below given figure, a tower AB is 20 m high and BC, its shadow on the ground, is 20√3 m long. Find the sun’s altitude.
Without using trigonometrical tables, evaluate:
`cosec^2 57^circ - tan^2 33^circ + cos 44^circ cosec 46^circ - sqrt(2) cos 45^circ - tan^2 60^circ`
Without using tables evaluate: 3cos 80°. cosec 10° + 2sin 59° sec 31°
Without using trigonometric tables, evaluate :
`sin 16^circ/cos 74^circ`
Without using trigonometric tables, evaluate :
`cos 35^circ/sin 55^circ`
Without using trigonometric tables, evaluate :
`("cosec" 42^circ)/sec 48^circ`
Without using trigonometric tables, prove that:
tan 71° − cot 19° = 0
Without using trigonometric tables, prove that:
cosec 80° − sec 10° = 0
Prove that:
`(sin 70^circ)/(cos 20^circ) + ("cosec" 20^circ)/(sec 70^circ) - 2 cos 70^circ "cosec" 20^circ = 0`
Prove that:
`cos 80^circ/(sin 10^circ) + cos 59^circ "cosec" 31^circ = 2`
Prove that:
\[\frac{sin\theta \cos(90° - \theta)cos\theta}{\sin(90° - \theta)} + \frac{cos\theta \sin(90° - \theta)sin\theta}{\cos(90° - \theta)}\]
Prove that:
\[cot\theta \tan\left( 90° - \theta \right) - \sec\left( 90° - \theta \right)cosec\theta + \sqrt{3}\tan12° \tan60° \tan78° = 2\]
Prove that:
cos1° cos2° cos3° ... cos180° = 0
Given that `tan (θ_1 + θ_2) = (tan θ_1 + tan θ_2)/(1 - tan θ_1 tan θ_2)` Find (θ1 + θ2) when tan θ1 = `1/2 and tan θ_2 = 1/3`.
Without using trigonometric tables, find the value of (sin 72° + cos 18°)(sin 72° - cos 18°).
Without using tables evaluate: `(2tan 53°)/(cot 37°) - (cot 80°)/(tan 10°)`.
From trigonometric table, write the values of sin 37°19'.
The length of a shadow of a tower standing on a level plane is found to be 2y meters longer when the seen's altitude is 30° than when it was 45° prove that the height of the tower is y ( √3 + 1 ) meter.
Given that sin θ = `a/b` then cos θ is equal to ______.