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प्रश्न
A line passes through the point (2, 2) and is perpendicular to the line 3x + y = 3. Its y-intercept is
पर्याय
\[\frac{1}{3}\]
2/3
1
4/3
उत्तर
4/3
The equation of the line perpendicular to 3x + y = 3 is given below:
x \[-\] 3y + \[\lambda\] = 0
This line passes through (2, 2)
2 \[-\] 6 + \[\lambda\] = 0
\[\Rightarrow \lambda = 4\]
So, the equation of the line will be
x\[-\] 3y + 4 = 0
\[\Rightarrow y = \frac{1}{3}x + \frac{4}{3}\]
Hence, the y-intercept is \[\frac{4}{3}\].
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