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A potential drop per unit length along a wire is 5 × 10−3 V/m. If the emf of a cell balances against length 216 cm of this potentiometer wire, find the emf of the cell. - Physics

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प्रश्न

A potential drop per unit length along a wire is 5 × 10−3 V/m. If the emf of a cell balances against length 216 cm of this potentiometer wire, find the emf of the cell.

बेरीज

उत्तर

Data: K = 5 × 10-3 `"V"/"m"`, L = 216 cm = 216 × 10-2 m

E = KL

∴ E = 5 × 10-3 × 216 ×10-2

= 1080 × 10-5

= 0.01080 V

The emf of the cell is 0.01080 volL

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पाठ 9: Current Electricity - Exercises [पृष्ठ २२९]

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बालभारती Physics [English] 12 Standard HSC Maharashtra State Board
पाठ 9 Current Electricity
Exercises | Q 17 | पृष्ठ २२९

संबंधित प्रश्‍न

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