Advertisements
Advertisements
प्रश्न
The area of a square garden is equal to the area of a rectangular plot of length 160m and width 40m. Calculate the cost of fencing the square garden at Rs.12per m.
उत्तर
The area of a rectangle with length l and breadth b = A = l x b
∴ The area of the rectangular plot with length 160m and breadth 40m
= A
= 160 x 40
= area of the square garden
We know,
The area of a square with side s = s2
∴ s2 = 160 x 40
⇒ s = `sqrt(160 xx 40)`
= `sqrt(16 xx 4 xx 100)`
= 4 x 2 x 10
= 80m
The perimeter of a square with side
= P
= 4s
∴ The perimeter of a square with side 80
= 4 x 80
= 320m
The cost of fencing at the rate of Rs.12per m
= 320 x 12
= Rs.3840.
APPEARS IN
संबंधित प्रश्न
Diagonal AC of a parallelogram ABCD bisects ∠A (see the given figure). Show that
- It bisects ∠C also,
- ABCD is a rhombus
ABCD is a trapezium in which AB || CD and AD = BC (see the given figure). Show that
- ∠A = ∠B
- ∠C = ∠D
- ΔABC ≅ ΔBAD
- diagonal AC = diagonal BD
[Hint: Extend AB and draw a line through C parallel to DA intersecting AB produced at E.]
In parallelogram ABCD, AP and AQ are perpendiculars from the vertex of obtuse angle A as shown.
If ∠x: ∠y = 2: 1.
find angles of the parallelogram.
State, 'true' or 'false'
The diagonals of a quadrilateral bisect each other.
State, 'true' or 'false'
Every rhombus is a parallelogram.
State, 'true' or 'false'
If two adjacent sides of a parallelogram are equal, it is a rhombus.
The given figure shows a square ABCD and an equilateral triangle ABP. 
Calculate: (i) ∠AOB
(ii) ∠BPC
(iii) ∠PCD
(iv) Reflex ∠APC
In the given figure, PQRS is a ∥ gm. A straight line through P cuts SR at point T and QR produced at N. Prove that area of triangle QTR is equal to the area of triangle STN.
In the figure, ABCD is a parallelogram and APD is an equilateral triangle of side 80cm, Calculate the area of parallelogram ABCD.
In the figure, if the area of ||gm PQRS is 84cm2; find the area of
(i) || gm PQMN
(ii) ΔPQS
(iii) ΔPQN
The diagonals of a parallelogram ABCD intersect at O. A line through O meets AB in P and CD in Q. Show that
(a) Area of APQD = `(1)/(2)` area of || gm ABCD
(b) Area of APQD = Area of BPQC
If the medians of a ΔABBC intersect at G, show that ar(ΔAGB) = ar(ΔAGC) = ar(ΔBGC) = `(1)/(3)"ar(ΔABC)"`.
Find the area of each of the following figure:
Find the area of a parallelogram whose base is 12cm and the height is 5cm.
Inside a square field of side 44m, a square flower bed is prepared leaving a graved path all round the flower bed. The total cost of laying the flower bed at Rs.25per sq m. and gravelling the path at Rs.120per sq m. is Rs.80320. Find the width of the gravel path.
Each angle of a rectangle is a right angle.
The opposite sides of a trapezium are parallel.
Examine whether the following is a polygon. If it is not, say why?
Name polygon.
Make two more examples of this.
