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प्रश्न
A uniformly charged conducting sphere of 2.4 m diameter has a surface charge density of 80.0 μC/m2.
- Find the charge on the sphere.
- What is the total electric flux leaving the surface of the sphere?
उत्तर
R = `2.4/2 "m"` = 1.2 m,
σ = 80.0 μ /c m-2
= 80 × 10-6 C m-2
- As σ = `q/(4pi"R"^2)`
so, q = 4πR2 × σ
= 4 × 3.14 ×(1.22) × 80 ×10-6
or q = 1.45 × 10-3 C - Φ = `q/ε_0`
= `(1.45 xx 10^-3)/(8.85 xx 10^-12)`
= 1.64 × 108 N m2 C-1
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