मराठी

D and E Are Points on the Sides Ab and Ac Respectively of a δAbc Such that De║Bc. Find the Value of X, When Ad = 4cm, Db = (X – 4) Cm, Ae = 8cm and Ec = (3x – 19) Cm. - Mathematics

Advertisements
Advertisements

प्रश्न

D and E are points on the sides AB and AC respectively of a ΔABC such that DE║BC. Find the value of x, when

AD = 4cm, DB = (x – 4) cm, AE = 8cm and EC = (3x – 19) cm.  

उत्तर

In Δ ABC, it is given that DE ‖ BC.
Applying Thales’ theorem, we have :

`(AD)/(DB) = (AE)/(EC)`

⟹ `4/(x-4) = 8 /(3x -19)`

⟹ 4 (3x-19) = 8 (x-4)

⟹ 12x – 76 = 8x – 32

⟹ 4x = 44

⟹ x = 11 cm

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 4: Triangles - Exercises 1

APPEARS IN

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

In ΔABC, D and E are points on the sides AB and AC respectively such that DE || BC

If `"AD"/"DB"=3/4` and AC = 15 cm, find AE


In ΔABC, D and E are points on the sides AB and AC respectively such that DE || BC

If `"AD"/"BD"=4/5` and EC = 2.5 cm, find AE


In a ΔABC, D and E are points on the sides AB and AC respectively. For  the following case show that DE || BC

AB = 5.6cm, AD = 1.4cm, AC= 7.2 cm and AE = 1.8 cm.


In the given figure, ABCD is a trapezium in which AB║DC and its diagonals intersect at O. If AO = (5x – 7), OC = (2x + 1) , BO = (7x – 5) and OD = (7x + 1), find the value of x.  

 


Two vertical poles of height 9m and 14m stand on a plane ground. If the distance between their feet is 12m, find the distance between their tops. 


An aeroplane leaves an airport and flies due north at a speed of 1000km per hour. At the same time, another aeroplane leaves the same airport and flies due west at a speed of 1200 km per hour. How far apart will be the two planes after` 1 1/2`  hours?


From fig., seg PQ || side BC, AP = x + 3, PB = x – 3, AQ = x + 5, QC = x – 2, then complete the activity to find the value of x.

In ΔPQB, PQ || side BC

`"AP"/"PB" = "AQ"/(["______"])`    ...[______]

`(x + 3)/(x - 3) = (x + 5)/(["______"])`

(x + 3) [______] = (x + 5)(x – 3)

x2 + x – [______] = x2 + 2x – 15

x = [______]


In fig., PS = 2, SQ = 6, QR = 5, PT = x and TR = y. Then find the pair of value of x and y such that ST || side QR.


In the given figure, Sand Tare points on sides PQ and PR, respectively of ΔPQR such that ST is parallel to QR and SQ = TR. Prove that ΔPQR is an isosceles triangles.


In the given figure, ABC is a triangle in which DE||BC. If AD = x, DB = x – 2, AE = x + 2 and EC = x – 1, then find the value of x.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×